Edexcel UK AS 8CH0 / A-Level 9CH0 · Topic 2 · Year 12 / AS

Part 6: Giant structures and property evidence

Reviewed 9 October 2026.

Identify the particles in a solid, explain the forces connecting them and use several physical observations together to deduce an unfamiliar structure.

Bond type and structure answer different questions

Bonding describes attractions between particles. Structure describes how those particles are arranged and how far the connected arrangement extends. Covalent bonding can occur inside a small molecule or throughout a giant network; the word ‘covalent’ alone therefore cannot predict a melting temperature.

Ionic solids and metals have giant lattices. Diamond, graphite and silicon(IV) oxide have giant covalent structures. Solid iodine and ice have molecular structures: their molecules form a lattice, but the covalent bonds are confined within separate I₂ or H₂O units. The lattice in ice is connected by hydrogen bonds, not an uninterrupted covalent network.

Four structural models
StructureParticlesMain binding interactionExamples
Giant ionicCations and anionsOppositely charged ions attractNaCl, MgO
Giant metallicMetal cations and delocalised electronsCation–electron attractionMg, Al
Giant covalentAtoms linked throughout the structureCovalent bondsDiamond, graphite, SiO₂
Simple molecularSeparate moleculesIntermolecular attractions between moleculesI₂, ice, solid CO₂

Diamond and silicon dioxide: strong continuous networks

In diamond, each carbon forms four covalent bonds to four other carbons in a tetrahedral network. The rigid three-dimensional network gives hardness; extensive strong bonding gives a very high temperature for disruption. All four outer electrons per carbon participate in localised bonding, so pure diamond does not conduct electricity.

In silicon(IV) oxide, each silicon is bonded to four oxygens and each oxygen links two silicons, giving the overall SiO₂ ratio. It is a giant covalent network, not separate SiO₂ molecules. Its strong network explains high melting temperature, poor electrical conductivity and insolubility in water under ordinary conditions.

Water cannot simply pull individual molecules out of either network, because there are no separate molecules to remove. Dissolution would require extensive disruption of strong covalent bonding without sufficiently favourable replacement interactions.

Graphite and graphene separate strength from slipperiness

In graphite, each carbon forms three covalent bonds in a planar hexagonal layer. One outer electron per carbon contributes to a delocalised system extending across the layer. Mobile delocalised electrons allow electrical conduction, especially along the planes; do not say electrons are merely trapped in gaps between layers.

Strong covalent bonds within the sheets give high resistance to thermal disruption. Weaker attractions between the sheets allow them to slide, explaining softness and lubrication. ‘Weak bonds’ alone is misleading: it confuses the weak interlayer attractions with the strong intralayer covalent network.

Graphene is one carbon sheet with the same three-coordinate hexagonal bonding and delocalised electrons. It conducts along the sheet and has high tensile strength because of the strong covalent network. Its atomically thin structure differs from the many stacked layers in graphite. Properties of larger devices also depend on defects and contacts.

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Carbon structures: diamond, graphite and graphene

Labels to include:

  • Diamond: four tetrahedral covalent bonds per carbon
  • Graphite: planar hexagonal sheets, three covalent bonds per carbon
  • Graphite: weaker attractions between sheets
  • Delocalised electrons associated with each sheet; conduction along sheets
  • Graphene: one sheet, three bonds per carbon

The distinction between strong bonds within a sheet and weaker attractions between sheets explains how graphite can be soft yet resist heating. A finished lattice drawing remains outstanding; the connectivity and property explanations are complete.

Specify which charged particles are mobile

A molecular substance such as hydrogen chloride can form ions by reacting with water, so its aqueous solution conducts even though pure molecular HCl is not an ionic lattice. Similarly, a reactive metal disappearing in acid is undergoing a chemical reaction, not merely dissolving as neutral metal particles. Always state physical state and solvent when interpreting conductivity or solubility.

Structure and typical physical evidence
StructureMelting/boilingConductivityWater behaviour
Giant ionicOften high: strong ionic attractionsSolid: no; molten/dissolved: mobile ionsVariable; depends on lattice and hydration
MetallicOften high, but variableSolid and molten: mobile electronsUsually insoluble; some react with water
Giant covalentUsually very highUsually poor; graphite/graphene have mobile electronsUsually insoluble under ordinary conditions
MolecularOften lower; depends on intermolecular attractionsUsually poor: no mobile charged particlesDepends on solute–solvent attractions; some react/ionise

Use all observations before making a deduction

Constructed unknown A melts at a high temperature, does not conduct as a solid, conducts when molten and dissolves to give a conducting aqueous solution. A giant ionic structure is the consistent model: strong attractions resist melting, fixed solid ions cannot carry current, and molten or hydrated ions can move.

Constructed B is soft, conducts as a solid, is insoluble in water and remains solid at very high temperatures. A layered giant covalent structure such as graphite fits: delocalised electrons explain current, weak interlayer attractions explain sliding, and strong intralayer bonds explain thermal stability. ‘It conducts, so it must be metallic’ would discard the other evidence.

Constructed C melts at low temperature and does not conduct as a solid or melt. A simple molecular structure is plausible, because weak intermolecular attractions can be overcome with little energy and there are no mobile ions or delocalised electrons. Its water solubility still requires information about polarity, hydrogen bonding or reaction with water.

For an ‘explain’ response, connect structure → relevant particles/interactions → energy or mobility → observed property. A label plus an unconnected list of facts is weaker than a causal explanation. In the 2023 AS Q5(d) context, the scheme linked named compounds directly to properties from the supplied table.

Quick checks

Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official Edexcel mark allocations.

Q1. Why can both diamond and iodine be called covalent, yet have very different melting behaviour?Show answer

Diamond is a giant covalent network: melting/disruption requires breaking many strong covalent bonds. Iodine consists of I₂ molecules; melting overcomes weaker London attractions between molecules while the I–I covalent bonds remain intact.

Q2. Explain graphite’s conductivity without saying it has free ions.Show answer

Each carbon forms three covalent bonds and contributes an electron to a delocalised system across a layer. These electrons can move and carry charge, especially along the planes. The carbon atoms do not become mobile ions.

Q3. Why is SiO₂ described as a formula ratio rather than a molecule?Show answer

Its covalent connectivity extends throughout a giant network. Each Si has four O neighbours and each O bridges two Si, giving Si:O = 1:2; there are no separate SiO₂ molecules in the ordinary solid.

Q4. An unknown conducts as a solid. Give two possible structural types and one useful extra observation.Show answer

It could be metallic or a conducting giant covalent material such as graphite. Malleability versus easy layer sliding, thermal data or other structural evidence could help distinguish them. Conductivity alone is insufficient.

Q5. Why is ‘all ionic compounds dissolve in water’ scientifically unsafe?Show answer

Dissolving requires lattice disruption and formation of hydration interactions, with the overall balance also involving mixing. Some lattices, including barium sulfate, remain only sparingly soluble. The presence of ions alone does not determine solubility.

Sources

Sources and examiner guidance (reviewed 9 October 2026)

Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.