Replace the fixed-orbit picture with shells, subshells and orbitals, then use electron counts to build configurations through krypton.
Three levels of organisation
A principal quantum shell is labelled n = 1, 2, 3, … and contains subshells. A subshell contains one or more orbitals. An orbital is a region of space in an atom associated with a high probability of finding an electron; it can hold up to two electrons with opposite spins. It is not a circular path followed by an electron.
The first four shells can contain at most 2, 8, 18 and 32 electrons respectively, following 2n². Capacity is different from filling order: the third shell can hold 18, although potassium’s next electron enters 4s before 3d fills. Spin is a quantum property represented by an arrow; opposite arrows do not mean electrons travel around a circle in opposite directions.
| Subshell | Number of orbitals | Maximum electrons | Shape required here |
|---|---|---|---|
| s | 1 | 2 | Spherical |
| p | 3 | 6 | Each orbital is dumbbell-shaped, with two lobes |
| d | 5 | 10 | Detailed shapes not required |
| f | 7 | 14 | Explains the capacity of shell 4; configurations beyond Z = 36 are not required |
An s orbital is a sphere; a p orbital has two lobes
A sketch of an s orbital represents a three-dimensional spherical region, often drawn as a circle with a curved equatorial line. A p orbital has two equal lobes on opposite sides of the nucleus. Both lobes belong to one orbital, so together they can hold at most two electrons. The three p orbitals are oriented at right angles to one another.
In 8CH0/01 June 2023 Q1(b), the examiner report distinguishes a sphere from a circle and opposite spin from opposite directions of travel. These distinctions describe the model accurately, rather than supplying alternative names for the same thing.
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Build configurations in a controlled order
For neutral atoms through Z = 36, use the filling sequence 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p. Put one electron into each equal-energy orbital of a subshell before pairing them, with parallel spins for those singly occupied orbitals. When a pair forms, its spins must be opposite. The total superscripts must equal the number of electrons.
Worked example: sulfur has Z = 16. Filling 1s² 2s² 2p⁶ uses ten electrons; 3s² uses two more, leaving four for 3p. Its configuration is 1s² 2s² 2p⁶ 3s² 3p⁴. The three 3p boxes contain one pair and two single electrons. Pairing two boxes while leaving the third empty would violate the singly-before-pairing rule.
For bromine, Z = 35, the configuration is [Ar] 3d¹⁰ 4s² 4p⁵. Writing occupied subshells in principal-shell order is common even though 4s was filled before 3d. Chromium and copper are exceptions to the simplest filling prediction: Cr is [Ar] 3d⁵ 4s¹ and Cu is [Ar] 3d¹⁰ 4s¹. Their closely spaced subshell energies make these arrangements lower in energy overall; do not force 4s² for these two atoms.
Count electrons first, then change the outer occupancy
For the s- and p-block ions required in Topic 1, remove outer-shell electrons to form cations and add electrons to the outer subshell to form anions. Calcium, [Ar] 4s², becomes Ca²⁺, [Ar]. Sulfur, [Ne] 3s² 3p⁴, becomes S²⁻, [Ne] 3s² 3p⁶ = [Ar]. Both ions have 18 electrons, but different nuclear charges and chemical behaviour.
For aluminium, [Ne] 3s² 3p¹, remove the 3p electron and then the two 3s electrons to give Al³⁺ = [Ne]. A bromide ion has 35 + 1 = 36 electrons and configuration [Ar] 3d¹⁰ 4s² 4p⁶. Check the final electron count independently; changing the nuclear charge to obtain the ion would change the element.
Topic 1 requires neutral atom configurations through krypton and s-/p-block ion configurations. Transition-metal ion configurations and the loss of 4s electrons from them are taught in Topic 15.
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Electron configuration explains the Periodic Table
The block identifies the subshell being filled in the periodic pattern: Groups 1 and 2 are s block, Groups 13–18 are p block, and the central series is d block. Helium has 1s², so its configuration is s block although it is placed with the chemically unreactive noble gases.
Elements in the same main group have the same number and pattern of outer electrons. Group 2 atoms have an outer ns² configuration and tend to lose two electrons; Group 7 halogens have ns²np⁵ and can gain one. Chemical properties repeat because these outer configurations repeat. The highest occupied principal shell gives the period, but the subshell filled across a d-block row belongs to the shell below it.
Quick checks
Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official Edexcel mark allocations.
Q1. How many electrons can one p orbital, a p subshell and the third shell each hold?Show answer
One p orbital holds two; three p orbitals make a p subshell holding six; the third shell contains 3s, 3p and 3d and holds 2 + 6 + 10 = 18. Do not use the subshell capacity for one orbital.
Q2. Write the full configuration of phosphorus (Z = 15) and describe its three 3p boxes.Show answer
1s² 2s² 2p⁶ 3s² 3p³. Each 3p orbital contains one electron, with the three arrows pointing the same way. Pairing begins only after all three are singly occupied.
Q3. Write the configurations of K⁺ (Z = 19) and Se²⁻ (Z = 34).Show answer
K⁺ has 18 electrons: 1s² 2s² 2p⁶ 3s² 3p⁶. Se²⁻ has 36: [Ar] 3d¹⁰ 4s² 4p⁶. Potassium loses one electron; selenium gains two.
Q4. A student writes chromium as [Ar] 3d⁴ 4s². Correct it and check the total.Show answer
The ground-state configuration is [Ar] 3d⁵ 4s¹. The count is 18 + 5 + 1 = 24. Chromium is an exception to the simple filling prediction because the occupied subshell energies are close.
Q5. An atom ends 3s² 3p⁵. Identify its block and explain one likely ion charge.Show answer
It is a p-block atom, chlorine, with seven outer electrons. Gaining one electron completes 3p, producing Cl⁻. The gained electron changes charge but does not change the number of protons.
Sources
Sources and examiner guidance (reviewed 9 October 2026)
- Pearson Edexcel 9CH0 specification, Issue 3 (February 2024) — Topic 1, printed pp. 7–8; checked against 8CH0 Topic 1, printed pp. 5–6. UK AS and A-Level scope.
- Chemrevise — Edexcel Atomic Structure and Periodic Table — Pages 1–6 reviewed as a secondary coverage reference. Teaching, data examples and questions here are original.
- Pearson 8CH0/01 June 2023 mark scheme — Q1(b–d), Q2(a), Q9; PDF pp. 5–7, 28–31. Read with the question paper; guidance remains question-specific.
- Pearson 8CH0/01 June 2023 examiner report — Q1–2 and Q9; PDF pp. 3, 7–8. Reviewed 9 October 2026.
- Pearson 8CH0/01 June 2023 question paper — Question context for Q1–2 and Q9. Original Finesse exercises below do not reproduce these questions.
Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.
