Understand aspirin preparation, recrystallisation, suction filtration, melting range and original yield calculations for AQA RP10.
What the solid preparation demonstrates
Required Practical 10 includes preparation of a pure organic solid and a test of purity, as well as preparation of a pure organic liquid. Aspirin is the solid example in the AQA handbook. These notes explain the reasoning; practical work follows the supervised, risk-assessed method supplied by your centre.
Salicylic acid (2-hydroxybenzenecarboxylic acid) reacts with ethanoic anhydride. Its phenolic OH is acylated to form an ester while its carboxylic acid group remains. An acid catalyst and controlled warming promote the reaction. Ethanoic acid is the other product.
Obtain the crude product
Measure the starting material accurately so its amount can be used in the yield calculation. Warm the reaction mixture under the specified conditions; unnecessary prolonged heating can promote unwanted reactions.
During the controlled aqueous work-up, excess anhydride is hydrolysed and the poorly water-soluble product precipitates. Collecting this solid does not yet establish purity: it may contain unreacted material or trapped mother liquor. Follow the order and cooling requirements of the approved method rather than improvising water addition to a reactive mixture.
Recrystallisation: exploit a change in solubility
Choose a solvent or solvent mixture in which the product dissolves well when hot but much less when cold, without reacting with the solvent. Soluble impurities should remain in the mother liquor; insoluble impurities can be removed by hot filtration when that step is needed.
Dissolve the crude solid in the minimum practical volume of hot solvent. Too much solvent leaves more product dissolved after cooling and reduces recovery. In the aspirin handbook example, an ethanol/water mixture is used; the exact solvent choice belongs to the particular preparation.
Allow the solution to cool slowly so crystals grow, then use further cooling if the method calls for it. Collect the crystals by suction filtration. Rinse them with a small amount of suitable cold solvent to remove adhering solution while limiting product loss. Dry them before weighing and measuring the melting range.
Purification trades some recovery for purity. Transfer losses and product left in the mother liquor lower the isolated yield. Wet crystals can give an artificially high mass and a misleading yield, sometimes above 100%.
Why suction filtration needs a seal
A Büchner funnel with correctly fitted filter paper sits in a side-arm flask through a sealing collar. Reduced pressure draws the liquid through; crystals remain on the paper. The seal makes the pressure difference effective. Use appropriate thick-walled equipment and the laboratory vacuum arrangement specified by the teacher.
Diagram placeholder
Diagram placeholder — labelled suction filtration
Labels to include:
- Büchner funnel drawn in cross-section with an open top
- Flat perforated plate covered by filter paper
- Crystals on the filter paper
- Sealing bung or rubber collar
- Side-arm flask containing filtrate
- Side arm connected to the approved vacuum source
Show the lower funnel stem open into the flask, not fused to it. Label the seal and paper explicitly. The solid stays above the filter; the mother liquor passes into the flask. AQA June 2022 Paper 2 Q05.4 specifically assessed the apparatus drawing.
Test purity with a melting range
Place a small, dry, finely powdered sample in a capillary tube. Heat slowly near the expected melting point and record the range from first melting to complete melting. Repeat with a fresh sample and compare with a reliable value for the intended compound.
A reasonably pure sample usually melts over a narrow range close to the reference value. Soluble impurities typically lower and broaden the range. Do not say that every impurity must behave identically, or that one matching melting point proves identity and perfect purity. Decomposition on heating limits this method.
For example, a sample melting at 128–133 °C against a stated reference of 135–136 °C suggests impurities. A dry sample at 135–136 °C supports improved purity, but additional evidence such as TLC can strengthen the identification.
Worked yield and atom economy
Original calculation: 2.76 g of salicylic acid, Mr 138, reacts with excess ethanoic anhydride. Aspirin has Mr 180 and the molar ratio is 1:1. The amount of salicylic acid is 2.76 ÷ 138 = 0.0200 mol, so the theoretical aspirin mass is 0.0200 × 180 = 3.60 g.
If 2.70 g of dry, purified aspirin is collected, the percentage yield is 2.70 ÷ 3.60 × 100 = 75.0%. Use the limiting reagent; do not assume the larger weighed mass is limiting.
For the balanced anhydride route, the atom economy is 180 ÷ (138 + 102) × 100 = 75.0%. The numerical match to the yield in this example is coincidental. The ethanoic acid by-product accounts for the remaining atoms, even if a process can recover it.
The AQA practical handbook discusses comparing the anhydride and acyl chloride routes. A higher atom economy does not erase other considerations such as corrosive HCl formation, reagent handling, cost or purification.
Quick checks
Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official AQA mark allocations.
Q1. Which group in salicylic acid is acylated when aspirin is made?Show answer
The phenolic OH group. An ethanoyl group is attached through this oxygen to form an ester; the carboxylic acid group remains.
Q2. Why use the minimum amount of hot recrystallisation solvent?Show answer
Enough is needed to dissolve the product when hot, but excess solvent leaves more product in solution when cold and lowers crystal recovery.
Q3. Why must purified crystals be dry before weighing?Show answer
Retained solvent or water increases the measured mass, giving an artificially high yield. It can also interfere with the melting-range measurement.
Q4. 1.38 g of salicylic acid gives 1.35 g of dry aspirin. Calculate the yield using Mr values 138 and 180.Show answer
n = 1.38/138 = 0.0100 mol. Theoretical mass = 0.0100 × 180 = 1.80 g. Yield = 1.35/1.80 × 100 = 75.0%.
Q5. What does a broad melting range below the reference value usually suggest?Show answer
Impurities. Compare a dry sample with a reliable reference and heat slowly near the melting point. A narrow matching range supports purity but does not prove identity by itself.
Sources
Sources and examiner guidance (reviewed 2 October 2026)
- AQA 7405 organic chemistry specification — 3.3.14 coverage and required skills.
- Chemrevise: Organic Synthesis — Coverage checklist; explanations, data exercises and quick checks on this page are original Finesse material.
- AQA June 2023 Paper 2 mark scheme — Q06.4 (pp25–26) and examiner report p5: separation of close-boiling liquids. Practical guidance is also grounded in the AQA handbook.
- AQA June 2023 Paper 2 examiner report — Read alongside the question-specific marking guidance; not a universal wording checklist.
- AQA June 2022 Paper 2 mark scheme — Q05 (pp22–24) and report p5: organic work-up, drying, apparatus and yield; Q10 (pp32–33) and report p7: synthesis involving amines.
- AQA June 2022 Paper 2 examiner report — Read with the matching question context described in the mark-scheme source.
- AQA practical handbook: Required Practical 10 — Solid preparation and melting point pp136–140; liquid preparation pp143–147. Follow your centre’s risk-assessed method.
Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.
