Plan AQA organic syntheses of up to four steps, track carbon atoms and compare yield, atom economy and practical choices.
Start with the target, then work backwards
Identify the target functional group and the carbon skeleton separately. Ask which reaction makes the final bond or functional group, then which starting material that reaction needs. Repeat until you reach the supplied reactant. Finally read the route forwards and check every intermediate, reagent and condition.
Changing an alcohol into an aldehyde does not lengthen its carbon chain. Replacing a halogen by CN adds one carbon; reducing that nitrile keeps this new carbon. A reagent name alone does not demonstrate a route: draw or write each intermediate unambiguously.
A compact reaction toolkit
These are route-planning reminders. The individual topic notes explain mechanisms and limitations. Separate steps may need isolation or a change of conditions; listing mutually incompatible reagents together is not a valid one-pot method.
| Transformation | Reagents and conditions | Planning consequence |
|---|---|---|
| Halogenoalkane → alcohol | Aqueous NaOH or KOH; heat | Nucleophilic substitution; same carbon count |
| Halogenoalkane → alkene | Ethanolic KOH; heat | Elimination; may give positional isomers |
| Halogenoalkane → nitrile | KCN in aqueous ethanol; heat under reflux | Substitution; adds one carbon |
| Halogenoalkane → primary amine | Excess ethanolic ammonia; heat in suitable pressure apparatus | Further alkylation is a competing reaction |
| Nitrile → primary amine | Hydrogen with a nickel catalyst under suitable conditions, or LiAlH4 in dry ether followed by work-up | The nitrile carbon becomes CH2; NaBH4 is not the standard reagent |
| Primary alcohol → aldehyde / acid | Acidified potassium dichromate(VI); distil aldehyde / reflux with excess oxidant for acid | Control oxidation and whether product stays in the flask |
| Secondary alcohol → ketone | Acidified potassium dichromate(VI); heat | Tertiary alcohols resist this usual oxidation |
| Aldehyde or ketone → alcohol | NaBH4 in a suitable aqueous/alcoholic medium | Reduction; carbon skeleton unchanged |
| Alcohol → alkene → halogenoalkane | Concentrated H2SO4 or H3PO4 and heat; then hydrogen halide | Elimination followed by electrophilic addition |
| Carboxylic acid + alcohol → ester | Concentrated H2SO4 catalyst; heat under reflux | Reversible; subsequent separation and purification needed |
| Acyl chloride + primary amine → N-substituted amide | Suitable controlled conditions; excess amine or another base | Nucleophilic addition–elimination; neutralise the HCl formed |
| Benzene → nitrobenzene → phenylamine | Concentrated HNO3/H2SO4 at about 50–55 °C; then Sn/HCl and heat, followed by NaOH | Electrophilic substitution, reduction, then release the free amine |
| Benzene → aromatic ketone | Acyl chloride and anhydrous AlCl3; controlled conditions | Friedel–Crafts acylation; new carbon–carbon bond |
Worked four-step route: ethanol to propylamine
The target contains three carbons but ethanol contains two. Plan a nitrile intermediate to supply the extra carbon. This is one chemically valid four-step route; it is not a claim that industry would choose it.
Step 1: dehydrate ethanol with concentrated phosphoric acid and heat to form ethene. Step 2: add HBr to ethene to form bromoethane. Step 3: heat bromoethane with KCN in aqueous ethanol under reflux to form propanenitrile. Step 4: reduce propanenitrile with H2/Ni under suitable conditions to give propylamine (propan-1-amine).
Diagram placeholder
Diagram placeholder — four-step synthesis map
Labels to include:
- Ethanol: two carbon atoms
- Ethene: two carbon atoms
- Bromoethane: two carbon atoms
- Propanenitrile: highlight the new CN carbon
- Propylamine: the highlighted carbon is now CH2NH2
- Put a separate reagent and condition above every arrow
Draw the five structures in sequence. Keep the original two-carbon fragment in one colour and the cyanide carbon in another. The map must show four reaction arrows, not treat reagent addition as a new intermediate.
Check compatibility and competing products
A molecule with two functional groups can react at both. An oxidant intended to oxidise a primary alcohol can also oxidise an aldehyde elsewhere. Strong acid or base can hydrolyse an ester. Check the whole structure before choosing a reagent.
A racemic intermediate may remain racemic unless a later step separates or selectively transforms its enantiomers. A constitutional isomer mixture may need separation. Do not give a single pure product merely because it is the one you want.
For a synthesis ending in an amide, distinguish the carbonyl-containing acyl fragment from the amine fragment. N-ethylpropanamide needs a propanoyl group and an ethylamine group; ethanoyl chloride plus propylamine makes a different amide.
Yield multiplies; atom economy answers a different question
For consecutive steps with one-to-one stoichiometry, multiply fractional yields. If stoichiometric ratios change, calculate moles at each stage instead of blindly multiplying product masses.
A route with yields of 80.0%, 75.0% and 90.0% gives 0.800 × 0.750 × 0.900 = 0.540, or 54.0% overall. Starting with 0.200 mol of the limiting reactant can therefore produce 0.108 mol of the final product for this one-to-one route.
Atom economy = Mr of the desired product, including its stoichiometric coefficient, ÷ total Mr of all reactants with their coefficients × 100. It is calculated from a balanced equation, not the measured mass collected. High atom economy does not guarantee a high experimental yield.
When comparing routes, consider number of steps, yield, selectivity, atom economy, energy, separation, solvent use and reagent hazards. Avoid unnecessary solvents and hazardous substances where a workable alternative exists. A shorter route is not automatically better if it needs difficult purification or a much more hazardous reagent.
Explain why your route works
In AQA June 2022 Paper 2 Q10, the route involves amine chemistry and structural deduction. The report discusses difficulties with reagents and further reactions; use that context to practise connecting a named transformation to the actual structure.
For each arrow, check the functional-group change, carbon count, charge and conditions. State a necessary work-up, such as adding alkali after reducing nitrobenzene in acid, rather than presenting an ammonium salt as the free amine.
Quick checks
Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official AQA mark allocations.
Q1. Why does bromoethane react with cyanide to give a three-carbon product?Show answer
The carbon atom of CN− forms a bond to the carbon that originally carried Br. CH3CH2CN therefore contains three carbons.
Q2. Give the reagents for converting a primary alcohol into an aldehyde rather than the carboxylic acid.Show answer
Heat with acidified potassium dichromate(VI), using controlled oxidation and distilling off the aldehyde as it forms. Reflux with excess oxidant favours further oxidation to the acid.
Q3. A three-step one-to-one route has yields 90%, 80% and 75%. What is its overall yield?Show answer
0.90 × 0.80 × 0.75 × 100 = 54%. Do not average the three percentages.
Q4. Which two organic reactants can make N-ethylpropanamide by acylation?Show answer
Propanoyl chloride and ethylamine. Use excess amine or another suitable base to deal with the HCl formed. The product is CH3CH2CONHCH2CH3.
Q5. A route has fewer steps but a lower yield and uses a hazardous solvent. Is it necessarily greener?Show answer
No. Compare material consumption and waste, atom economy, yield, solvent hazards and recovery, energy and purification. Step count alone cannot settle the comparison.
Sources
Sources and examiner guidance (reviewed 2 October 2026)
- AQA 7405 organic chemistry specification — 3.3.14 coverage and required skills.
- Chemrevise: Organic Synthesis — Coverage checklist; explanations, data exercises and quick checks on this page are original Finesse material.
- AQA June 2023 Paper 2 mark scheme — Q06.4 (pp25–26) and examiner report p5: separation of close-boiling liquids. Practical guidance is also grounded in the AQA handbook.
- AQA June 2023 Paper 2 examiner report — Read alongside the question-specific marking guidance; not a universal wording checklist.
- AQA June 2022 Paper 2 mark scheme — Q05 (pp22–24) and report p5: organic work-up, drying, apparatus and yield; Q10 (pp32–33) and report p7: synthesis involving amines.
- AQA June 2022 Paper 2 examiner report — Read with the matching question context described in the mark-scheme source.
- AQA practical handbook: Required Practical 10 — Solid preparation and melting point pp136–140; liquid preparation pp143–147. Follow your centre’s risk-assessed method.
Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.
