AQA A-Level Chemistry 7405 · 3.3.5 Alcohols

Part 2: Oxidation, reflux and identifying products

All 3 parts available · worked answers and exam guidance included. Reviewed 2 October 2026.

Choose conditions that stop a primary alcohol at an aldehyde or oxidise it to an acid, and distinguish those products from ketones.

The OH-bearing carbon decides the pathway

Warm an appropriate alcohol with potassium dichromate(VI) acidified using dilute sulfuric acid. When oxidation occurs, orange dichromate(VI) is reduced to green chromium(III). The alcohol is oxidised while the oxidising agent is reduced.

Primary alcohols can form aldehydes and then carboxylic acids. Secondary alcohols form ketones. Tertiary alcohols have no C–H bond on the OH-bearing carbon, so they resist oxidation by acidified dichromate under these normal conditions. This is not a claim that tertiary alcohols can never be destroyed by any oxidising conditions.

Choose the starting structure
Alcohol classInitial organic productFurther oxidation under these conditions
PrimaryAldehydeCarboxylic acid
SecondaryKetoneNormally no further oxidation
TertiaryNo usual oxidation productOrange reagent remains under the standard test conditions

Use [O] as oxidant bookkeeping

[O] is a convenient representation of oxygen supplied by an oxidising agent; it is not the reagent bottle label. You still need acidified potassium dichromate(VI) when asked for the reagent. Write CHO for a condensed aldehyde group, so the C=O connectivity is clear.

The examples below use butan-1-ol and butan-2-ol. Compare the hydrogen counts: conversion of an alcohol to a carbonyl removes two hydrogens, while conversion of the aldehyde to an acid adds oxygen.

CH₃CH₂CH₂CH₂OH + [O] → CH₃CH₂CH₂CHO + H₂O
CH₃CH₂CH₂CHO + [O] → CH₃CH₂CH₂COOH
CH₃CH₂CH₂CH₂OH + 2[O] → CH₃CH₂CH₂COOH + H₂O
CH₃CH(OH)CH₂CH₃ + [O] → CH₃COCH₂CH₃ + H₂O

Distil an aldehyde; reflux for an acid

To favour an aldehyde, use limited oxidant, warm gently and distil the volatile aldehyde away as it forms. Removing it reduces its contact with oxidant and therefore further oxidation. A cooled receiver can reduce loss of a volatile product.

To obtain a carboxylic acid, use excess oxidant and heat under reflux. A vertical condenser returns condensed vapour to the flask, allowing prolonged heating with reduced loss of volatile material. Reflux does not collect a separate distillate or by itself guarantee completion.

In distillation, position the thermometer bulb beside the side-arm opening to measure the vapour entering the condenser. In both arrangements, cooling water enters the jacket at the bottom and exits at the top. Add anti-bumping granules before heating; use suitable electrical heating and leave the apparatus open to the atmosphere.

Diagram placeholder

Oxidation apparatus: distillation beside reflux

Labels to include:

  • reaction flask
  • limited versus excess oxidant
  • side-arm thermometer for distillation
  • sloping condenser to receiver
  • vertical reflux condenser
  • water in below and out above
  • open apparatus

For the aldehyde route, vapour travels through a sloping condenser to a separate receiver. For the acid route, vapour rises into a vertical condenser and the liquid runs back into the same flask. Label the destination of the condensed liquid, because it explains why one arrangement removes aldehyde while the other keeps reactants together.

Distinguish an aldehyde from a ketone

Tollens’ reagent contains the diamminesilver(I) complex in alkaline solution. Warm gently: a typical aldehyde gives a silver mirror or silver deposit; a simple ketone gives no visible change. The aldehyde is oxidised and silver(I) is reduced to silver metal.

Fehling’s solution is an alkaline copper(II) reagent. On warming with a typical aliphatic aldehyde, the blue solution produces a brick-red precipitate of Cu₂O. A simple ketone leaves the blue solution without that precipitate. The organic oxidation product in these alkaline mixtures is a carboxylate ion, not predominantly the free acid.

Use freshly prepared Tollens’ reagent only in a supervised test and dispose of it promptly under the laboratory procedure; do not store it or let residues dry. Do not use acidified dichromate alone to distinguish an aldehyde from a primary or secondary alcohol, because both can reduce it.

Quick checks

Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official AQA mark allocations.

Q1. Give the product, reagent and conditions for turning pentan-1-ol into pentanal.Show answer

Use potassium dichromate(VI) with dilute sulfuric acid, limited oxidant and gentle warming. Distil pentanal away as it forms to reduce further oxidation.

Q2. Write the [O] equation for oxidising propan-2-ol.Show answer

CH₃CH(OH)CH₃ + [O] → CH₃COCH₃ + H₂O. The product is propanone.

Q3. Why does 2-methylpropan-2-ol resist oxidation in this test?Show answer

The carbon bearing OH has no hydrogen attached. The usual conversion to a carbonyl cannot occur without breaking a C–C bond.

Q4. How does reflux differ from distillation in the destination of the condensed liquid?Show answer

In reflux it returns to the reaction flask. In distillation it is collected separately. This controls whether a volatile product remains exposed to the reagents.

Q5. Suggest a test distinguishing butanal from butan-2-one and state both outcomes.Show answer

Warm separate samples with Tollens’ reagent. Butanal gives a silver mirror/deposit; butan-2-one gives no visible change. Alternatively, warm with Fehling’s: butanal gives a brick-red precipitate; butan-2-one remains blue without that precipitate.

Sources

Sources and examiner guidance (reviewed 2 October 2026)

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