Explain the purpose of reflux, recrystallisation, filtration and melting-point measurement, including how practical errors change yield and purity.
Match the apparatus to the physical task
A preparation may use Quickfit apparatus to heat a reaction under reflux or to distil a volatile component. In reflux the condenser is vertical above the reaction vessel, cooling vapour so liquid returns. In distillation the vapour passes through a condenser towards a separate receiver.
Cooling water enters a condenser at the lower inlet and leaves at the upper outlet so the jacket fills effectively. The apparatus must not become a sealed heated system. Use suitable clamping and a heating method compatible with the flammability and hazards of the mixture.
Anti-bumping granules provide nucleation sites for smoother boiling when appropriate. Add them before heating; adding them to a hot superheated liquid can cause sudden boiling. These explanations connect apparatus features to purpose rather than merely naming glassware.
Exploit a temperature-dependent solubility difference
Recrystallisation works when the desired solid is much more soluble in the chosen solvent when hot than when cold. Dissolve the crude solid in the minimum practical volume of hot solvent. Too much solvent leaves more product dissolved after cooling and lowers recovery.
If insoluble impurities remain, filter the hot solution while keeping it hot enough to avoid premature product crystallisation in the funnel. This removes insoluble material; it is not the same operation as later collecting the product crystals.
Allow the solution to cool so crystals form. Slow initial cooling can favour better crystal growth; further cooling can improve recovery. Soluble impurities ideally remain in the mother liquor, while product molecules enter the crystal lattice. A solvent must also be chemically suitable, not react with the product, and be manageable to remove.
Wash impurities away without redissolving the product
Collect crystals by filtration under reduced pressure using suitable apparatus such as a Büchner funnel and side-arm flask. Wet the filter paper with the chosen solvent so it seats properly, and use apparatus appropriate to reduced pressure.
Wash with a small amount of cold solvent to remove adhering mother liquor and its soluble impurities. Hot solvent or a large washing volume can dissolve product and reduce yield. Continue suction as appropriate, then dry the crystals by a suitable method before weighing or testing them.
Wet crystals can give an apparently high yield because retained solvent contributes mass. Drying is therefore part of obtaining a defensible yield, not just presentation. Transfer losses and product remaining in solution can lower recovery even when the reaction itself proceeded well.
Interpret a range, not a single reassuring number
A pure crystalline substance usually melts over a narrow range close to its reference melting point under comparable conditions. Impurities often depress and broaden the range. Heat slowly near the expected melting region and record onset and completion rather than a single guessed temperature.
Agreement supports identity and purity, but melting point alone is not absolute proof: different substances can have similar values and decomposition or measurement conditions can complicate interpretation. Combine it with the reaction route and other analytical evidence.
If the measured range is broad and low, consider impurity, residual solvent and technique. Recrystallising again may improve purity but usually reduces recovered mass. Explain the purity–recovery trade-off instead of assuming the highest mass is the best product.
Worked example: distinguish yield from purity
An original preparation has a theoretical product mass of 3.20 g. Dry purified crystals weigh 2.24 g, giving percentage yield = 2.24/3.20 × 100 = 70.0%. An earlier wet mass of 3.36 g would suggest 105%, signalling that the weighed material cannot all be dry pure product under the stated assumptions.
A low yield alone does not identify the cause. The reaction may be incomplete, side reactions may occur, some solid may remain dissolved, or product may be lost during transfer and filtration. Match a proposed improvement to evidence about the actual loss.
Practical questions can assess why a method works, how uncertainty enters and how changes affect results. Written knowledge of this procedure is distinct from demonstrating the practical competencies required for the practical endorsement; completing these notes does not itself satisfy the endorsement.
Quick checks
Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official OCR A mark allocations.
Q1. Why use the minimum amount of hot solvent in recrystallisation?Show answer
It dissolves the product when hot while limiting how much remains dissolved after cooling. Excess solvent reduces crystal recovery.
Q2. What is removed by hot filtration, and what is collected by the later cold filtration?Show answer
Hot filtration removes insoluble impurities while the product remains dissolved. After cooling, the later filtration collects the crystallised product.
Q3. Why wash crystals with a small volume of cold solvent?Show answer
It removes adhering solution and soluble impurities while minimising dissolution of the product. Hot or excessive solvent can lower recovery.
Q4. A student obtains 112% yield from freshly filtered crystals. Give a plausible explanation and check.Show answer
Retained solvent or other impurities may add mass. Dry the product appropriately and reweigh; also check theoretical-yield stoichiometry and balance readings.
Q5. What does a broad melting range below a reference value suggest, and what does it not prove?Show answer
It suggests impurity or residual solvent, although technique can also affect the result. It does not uniquely identify the impurity or prove a particular structure; use further evidence.
Sources
Sources and examiner guidance (reviewed 6 October 2026)
- OCR A H432 specification — version 3.1 — 6.2.5, printed pp. 60–61; outcomes and additional guidance, with relevant Module 1 practical skills.
- Chemrevise — OCR A 6.2.5 — Pages 1–5; secondary coverage cross-check. Lesson explanations, data and questions are original Finesse material.
- OCR H432/02 mark scheme — June 2025 — Q19(b), Q21(e); printed pp. 21–23,32. Question-specific evidence, not universal marking rules.
- OCR H432/02 examiner report — June 2025 — Q19(b), Q21(e); printed pp. 34–36,47–48. Read with the corresponding question context.
- OCR H432/02 question paper — June 2025 — Q19(b), Q21(e); context for the assessment references, not reproduced questions.
Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.
