Use chemical environments, symmetry, TMS and carbon-13 chemical shifts to interpret AQA NMR spectra.
What NMR measures
Nuclei such as 1H and 13C interact with a strong magnetic field. Radiofrequency energy can be absorbed at resonance. The electrons and nearby groups affect the field experienced by a nucleus, so nuclei in different chemical environments can resonate at different frequencies.
The spectrum plots signal against chemical shift, δ, in parts per million (ppm). A shift is measured relative to a reference, normally tetramethylsilane, TMS. Larger δ values are generally plotted towards the left. Use the actual axis labels rather than assuming left means “lower”.
Carbon-13 NMR tells you about carbon environments. Proton NMR tells you about hydrogen environments and also provides useful relative areas and splitting. Standard A-Level 13C spectra are treated as proton-decoupled: each distinct carbon environment gives a single signal. Do not apply the proton n + 1 rule to those carbon spectra.
Why TMS and deuterated solvents are used
TMS is Si(CH3)4. Its four carbon atoms are equivalent and its twelve hydrogen atoms are equivalent, so it gives one reference signal in each type of spectrum. The reference is assigned δ = 0 ppm. TMS is comparatively unreactive, volatile and gives a signal well separated from most ordinary organic signals. A reference peak is not an extra environment in the unknown.
A suitable solvent dissolves the sample without reacting with it. Deuterated solvents such as CDCl3 greatly reduce the solvent signal in a proton spectrum because deuterium is 2H rather than 1H. Real solvents can contain residual protonated solvent and water, so “no solvent peaks under any circumstances” is too absolute.
Deuterated carbon-containing solvents can still produce 13C signals. Recognise labelled solvent/reference signals and exclude them when counting sample environments. CCl4 contains no hydrogen and may appear in theoretical questions, but it is hazardous and is not a default recommendation for practical solvent choice.
Count environments, not just atoms
Equivalent carbons have the same chemical surroundings. Symmetry can make different positions equivalent, but simply being a CH3 carbon does not. Compare the whole molecular structure, including the positions of functional groups.
Propanone, CH3COCH3, has three carbons but only two environments: the two methyl groups are equivalent and the carbonyl carbon is different. Propanal, CH3CH2CHO, has three carbon environments.
Butan-2-one has four environments because its two methyl groups occupy different surroundings. 2-Methylpropanal, (CH3)2CHCHO, has three because its two methyl groups are equivalent. For ordinary benzene, symmetry makes all six ring carbons equivalent.
| Compound | Carbon atoms | Expected sample 13C signals |
|---|---|---|
| Ethane | 2 | 1 |
| Propan-1-ol | 3 | 3 |
| Propan-2-ol | 3 | 2 |
| Ethyl ethanoate | 4 | 4 |
| 2-Methylpropan-2-ol | 4 | 2 |
| Benzene | 6 | 1 |
Diagram placeholder
Diagram placeholder — label equivalent carbon positions
Labels to include:
- Propanone: label both CH3 carbons a and the carbonyl carbon b
- Butan-2-one: label all four carbons differently
- 2-Methylpropanal: give its two methyl carbons the same label
- Benzene: give every ring carbon the same label
- Count labels, not the number of written C symbols
Draw full carbon skeletons and colour equivalent positions consistently. In butan-2-one a methyl attached to C=O is not equivalent to the terminal methyl of its ethyl group.
Use the carbon-13 shift ranges
Use the AQA data booklet supplied with the question. Ranges overlap and neighbouring groups can shift a signal, so a single δ value is evidence for an environment rather than a complete structural identification.
| Environment | Range | Interpretation |
|---|---|---|
| Alkyl carbon | 5–40 | Saturated carbon without a strongly shifting attachment |
| C bonded to Cl or Br | 10–70 | Overlaps several other ranges |
| C adjacent to C=O | 20–50 | This is not the carbonyl carbon itself |
| C bonded to N | 25–60 | Use alongside formula and other evidence |
| C bonded to O in alcohols, ethers or esters | 50–90 | Single-bonded oxygen attachment |
| Alkene C=C | 90–150 | Compare with aromatic and nitrile ranges |
| Nitrile carbon | 110–125 | Support with C≡N evidence from IR |
| Aromatic carbon | 110–160 | Signal count also depends on ring symmetry |
| Carboxylic acid or ester C=O | 160–185 | Does not alone distinguish acid from ester |
| Aldehyde or ketone C=O | 190–220 | Use further evidence to distinguish the two |
Worked deduction from carbon-13 data
Original teaching data: a compound has molecular formula C4H8O and four sample 13C signals at approximately δ 8, 29, 36 and 209 ppm. The high-shift signal supports an aldehyde or ketone carbonyl; the other three indicate saturated carbon environments.
Butan-2-one is consistent with four environments and a ketone carbonyl. The data do not justify identifying it uniquely on signal count alone: butanal also has four environments and a carbonyl. Additional proton NMR or aldehyde-test evidence can distinguish them.
An ordinary 13C peak area is not a reliable count of the number of carbons represented. Four signals do not mean the molecule necessarily contains exactly four carbons, and a weak or overlapping signal can complicate a real spectrum.
Give a structural reason for each assignment
AQA June 2023 Paper 2 Q05 separates counting carbon environments from explaining proton shifts and splitting. Its examiner report discusses difficulty recognising the environments and using incomplete spectra. Make a labelled structure and check all of its predicted environments against the data.
In an exam spectrum, use any stated simplifications. Do not add imagined solvent peaks or missing signals, but recognise explicitly stated overlap or incomplete information when evaluating whether a structure is uniquely determined.
Quick checks
Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official AQA mark allocations.
Q1. Why does TMS give only one signal in a proton spectrum?Show answer
All twelve of its hydrogen atoms are chemically equivalent. The signal is assigned δ = 0 ppm as the reference.
Q2. How many 13C signals are expected for propan-2-ol, and why?Show answer
Two. The two methyl carbons are equivalent; the carbon bearing OH is a different environment.
Q3. Can a carbon signal near δ 175 ppm distinguish an ester from a carboxylic acid by itself?Show answer
No. Both have carbonyl carbons in the AQA 160–185 ppm range. Use IR, proton NMR and the formula or other evidence.
Q4. Why can a deuterated solvent still appear in a 13C spectrum?Show answer
Replacing 1H by 2H does not remove the solvent’s carbon atoms. A carbon-containing deuterated solvent can give a carbon signal.
Q5. A molecule has six carbon atoms but only three carbon signals. Is this impossible?Show answer
No. Symmetry can make some carbons equivalent. Three signals indicate three distinguishable sample environments under the stated conditions, not necessarily three atoms.
Sources
Sources and examiner guidance (reviewed 2 October 2026)
- AQA 7405 organic chemistry specification — 3.3.15 coverage and required skills.
- Chemrevise: NMR Spectroscopy — Coverage checklist; explanations, data exercises and quick checks on this page are original Finesse material.
- AQA June 2023 Paper 2 mark scheme — Q05 (pp22–24) and examiner report p4: environments, shift versus splitting, overlap and missing integration.
- AQA June 2023 Paper 2 examiner report — Read alongside the question-specific marking guidance; not a universal wording checklist.
- AQA June 2022 Paper 2 mark scheme — Q06.1 (p25) and report pp5–6: coherent combined IR, 1H and 13C interpretation.
- AQA June 2022 Paper 2 examiner report — Read with the matching question context described in the mark-scheme source.
- AQA Chemistry data booklet — Page 3: infrared and NMR ranges. Worked spectra here use original, idealised teaching data.
Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.
