Connect Group 2 structure to electron loss, then distinguish reactions with cold water, steam, oxygen and acids.
The common pattern: forming 2+ ions
Magnesium, calcium, strontium and barium have two outer s electrons: Mg [Ne]3s², Ca [Ar]4s², Sr [Kr]5s² and Ba [Xe]6s². Their usual ions are M²⁺. They act as reducing agents when the metal donates its two outer electrons.
The third ionisation energy is much greater than the second because the third electron is removed from an inner shell of the 2+ ion. Do not stop at “a full shell”: identify that the electron is closer to the nucleus and less shielded.
Down the group: radius rises and first ionisation energy falls
Each step down adds an occupied principal shell. The outer electron is farther from the nucleus and shielded by more inner electrons. Although proton number also increases, distance and shielding reduce the net attraction to the outer electron. Less energy is needed to remove it.
The metals generally react more vigorously down Mg–Ba because loss of the outer electrons becomes easier. Keep the electron-loss explanation separate from the collision-theory explanation for changing the temperature of one reaction.
Metallic bonding and the non-smooth melting-point pattern
All four are metallic: positive metal ions are attracted to delocalised electrons. Each contributes two electrons in the simple metallic model. Greater ion size tends to reduce attraction between ions and delocalised electrons, so less energy is needed to disrupt the lattice.
However, the actual melting points do not decrease at every step: calcium melts above magnesium (RSC values: Mg 650 °C; Ca 842 °C). Crystal structures also affect the pattern. Describe the data supplied instead of forcing a smooth decline; the simple size argument cannot explain every adjacent pair.
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Group 2 trends with the melting-point exception
Labels to include:
- Separate axes for atomic radius, first ionisation energy and melting point
- Elements: Mg, Ca, Sr, Ba
- Radius increases; first ionisation energy decreases
- Melting-point plot must show Ca above Mg; use a verified dataset for numerical points
- Metallic lattice inset: positive ions and delocalised electrons
The first two trends follow electron-shell reasoning. The melting-point pattern requires metallic bonding and awareness that crystal structure also matters.
Water versus steam: choose the right product
With liquid water, magnesium reacts very slowly at room temperature; warming makes its reaction easier to observe. A coating of sparingly soluble magnesium hydroxide limits contact. Heated magnesium reacts rapidly with steam to give magnesium oxide and hydrogen, often with a bright white glow.
Calcium, strontium and barium react with cold water, increasingly vigorously. Expect hydrogen bubbles, disappearance of the metal and warming. The dissolved hydroxide makes the mixture alkaline. Calcium hydroxide is only partly soluble, so a white cloudy suspension can form.
Use the state implied by the conditions: dissolved Ca(OH)₂ is (aq), but excess solid in the cloudy suspension is (s). Do not call all reaction mixtures clear solutions. Hydrogen gives a squeaky pop with a lighted splint when tested appropriately in a supervised practical.
Oxygen, surface coatings and acids
Magnesium burns in oxygen with an intense white light and forms white MgO. Its oxide has a giant ionic structure with strong attractions between oppositely charged ions. This gives a high melting point.
Before comparing magnesium reaction rates, clean off the surface coating with emery paper. MgO reacts with hydrochloric acid without producing hydrogen; magnesium metal produces hydrogen. A coating can therefore delay the gas-producing reaction and consume some acid.
With dilute hydrochloric acid, Group 2 metals form chlorides and hydrogen. Sulfuric acid can be a poor choice for comparing the more reactive metals: an insoluble sulfate coating can restrict further reaction. Nitric acid is oxidising, so do not automatically predict hydrogen with every acid.
Quick checks
Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official AQA mark allocations.
Q1. Why is the first ionisation energy of Ba lower than that of Mg despite Ba having more protons?Show answer
Ba has more occupied shells; its outer electron is farther from the nucleus and more shielded. The attraction to that electron is weaker, so removal requires less energy.
Q2. Write separate equations for magnesium reacting with liquid water and with steam.Show answer
Liquid water: Mg + 2H₂O → Mg(OH)₂ + H₂. Steam: Mg + H₂O → MgO + H₂. The products differ: hydroxide versus oxide.
Q3. Explain why a calcium–water mixture may be cloudy and alkaline at the same time.Show answer
Some Ca(OH)₂ remains as suspended white solid because it is only partly soluble. The portion that dissolves releases OH⁻, making the liquid alkaline.
Q4. A student says Group 2 melting points must decrease at every step. Evaluate this using Mg 650 °C and Ca 842 °C.Show answer
The claim is contradicted by the data: the melting point rises from Mg to Ca. Ion size alone is not enough; the metallic crystal structure also affects melting.
Q5. Calculate the theoretical moles of H₂ from 0.486 g of Mg reacting completely with excess dilute HCl. Use Ar(Mg) = 24.3.Show answer
n(Mg) = 0.486 ÷ 24.3 = 0.0200 mol. Mg:H₂ is 1:1, so n(H₂) = 0.0200 mol.
Sources
Sources and examiner guidance (reviewed 2 October 2026)
- Chemrevise — AQA 2.2 Group 2 (October 2025) — Primary coverage checklist, pp1–4; qualifications explained in the notes.
- AQA 7405 specification — 3.2.2 and relevant Required Practical 4 work.
- AQA 7404/1 June 2022 mark scheme — Q01.1–01.3, p11.
- AQA 7404/1 June 2022 examiner report — Q01, p3.
- RSC — Magnesium — Melting point checked against calcium.
- RSC — Calcium — Evidence that the Mg–Ca melting-point trend is not a decline.
Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.
