Use a mole table before calculating pressure, then solve for Kp, total pressure or the extent of reaction.
Keep initial and equilibrium amounts separate
Start with a balanced equation and an initial–change–equilibrium table. Use one reaction extent so all changes follow the coefficients. Add the equilibrium amounts to obtain the equilibrium total; it need not equal the initial total. Convert to mole fractions, then partial pressures, then substitute into Kp.
Check that all equilibrium amounts are non-negative and no amount consumed exceeds the starting amount. Carry unrounded fractions through the calculation. Early rounding is especially damaging when partial pressures are cubed.
Worked ammonia mixture
A closed vessel initially contains 1.50 mol N₂ and 4.50 mol H₂ with no NH₃. At equilibrium, 0.300 mol of nitrogen has reacted. Total pressure is 200 kPa.
| Stage / mol | N₂ | H₂ | NH₃ |
|---|---|---|---|
| Initial | 1.50 | 4.50 | 0 |
| Change | −0.300 | −0.900 | +0.600 |
| Equilibrium | 1.20 | 3.60 | 0.600 |
Rearrange to find total pressure
For N₂O₄(g) ⇌ 2NO₂(g), substitute p = xP to get Kp = x(NO₂)²P/x(N₂O₄). If the equilibrium mole fractions are 0.400 NO₂ and 0.600 N₂O₄ and Kp = 12.0 kPa, then P = 12.0 × 0.600/0.400² = 45.0 kPa.
Check by substitution: p(NO₂) = 18.0 and p(N₂O₄) = 27.0 kPa; 18.0²/27.0 = 12.0 kPa. In ammonia calculations the net power of P is −2, so recovering P requires a square root. Derive the power from the equation instead of memorising one rearrangement.
Solve for dissociation
Begin with 1.00 mol N₂O₄ and no NO₂. Let α be the fraction dissociated. At equilibrium there are (1 − α) mol N₂O₄ and 2α mol NO₂, total (1 + α) mol. Hence Kp = 4α²P/(1 − α²).
At P = 100 kPa and Kp = 25.0 kPa: 25.0(1 − α²) = 400α², giving α² = 25/425 and α = 0.2425. The physical root is positive and below one. Equilibrium amounts are 0.7575 mol N₂O₄ and 0.4851 mol NO₂. The fraction dissociated is 24.3%, but the NO₂ mole fraction is 0.390; those are different quantities.
Catch errors before submitting
Check the pressure sum, the Kp units and the equilibrium amount bounds. If a question supplies an equilibrium mass, convert it with the correct molar mass before finding the reaction extent. If products were present initially, include them in the initial row; do not assume every final product molecule was made during the experiment.
Use the stated ideal-gas assumption. Industrial mixtures at high pressure can deviate from ideal behaviour, but do not introduce unprovided corrections into an A-level calculation.
Quick checks
Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official AQA mark allocations.
Q1. Initially 2.00 mol SO₂ and 1.50 mol O₂ form 0.800 mol SO₃. Find equilibrium amounts for 2SO₂ + O₂ ⇌ 2SO₃.Show answer
SO₂ used = 0.800 mol; O₂ used = 0.400 mol. Equilibrium: 1.20 mol SO₂, 1.10 mol O₂ and 0.800 mol SO₃; total 3.10 mol.
Q2. For H₂ + I₂ ⇌ 2HI, equilibrium partial pressures are 10.0, 10.0 and 60.0 kPa. Find Kp.Show answer
Kp = 60.0²/(10.0 × 10.0) = 36.0, with no units.
Q3. For N₂O₄ ⇌ 2NO₂, x(NO₂) = 0.500 and Kp = 20.0 kPa. Find total pressure.Show answer
x(N₂O₄) = 0.500. P = 20.0 × 0.500/0.500² = 40.0 kPa.
Q4. One mole of N₂O₄ dissociates by 30.0%. Find the NO₂ mole fraction.Show answer
Equilibrium: 0.700 mol N₂O₄ and 0.600 mol NO₂, total 1.300 mol. x(NO₂) = 0.600/1.300 = 0.462.
Q5. Why reject α = −0.24 in this dissociation problem?Show answer
α represents a fraction of the initial N₂O₄ that dissociates. It must lie between zero and one; a negative root would give a negative NO₂ amount.
Sources
Sources and examiner guidance (reviewed 2 October 2026)
- AQA 7405 physical chemistry specification — 3.1.10 coverage and required skills.
- Chemrevise: Equilibrium constant Kp — Coverage checklist; explanations, data exercises and quick checks on this page are original Finesse material.
- AQA June 2023 Paper 1 mark scheme — Q04, pp16–17; report Q04, p4: partial pressures, total-pressure rearrangement and pressure versus temperature effects.
- AQA June 2023 Paper 1 examiner report — Read alongside the question-specific marking guidance; not a universal wording checklist.
Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.
