1. Electronegativity
Electronegativity is the power of an atom to attract the pair of electrons in a covalent bond. It is about the bonding pair, not a lone pair.
- Across a period it increases: nuclear charge rises, atomic radius falls and shielding stays similar, so the bonding pair is attracted more strongly.
- Down a group it decreases: the atom is larger and there is more shielding, so the bonding pair is further from the nucleus and attracted less.
Fluorine is the most electronegative element. Oxygen, nitrogen and chlorine also have high electronegativities.
2. Polar bonds
When two bonded atoms have different electronegativities, the bonding pair is shared unequally. The more electronegative atom gets a partial negative charge (δ−) and the other a partial positive charge (δ+): Hδ+–Clδ−. Bonds between identical atoms (Cl–Cl) are non-polar.
Bonding is a continuum: the bigger the electronegativity difference, the more polar the bond, until it becomes more ionic in character. There is no single universal cut-off value that separates "covalent" from "ionic".
3. Polar and non-polar molecules
A molecule can contain polar bonds and still be non-polar. A molecule is non-polar when its bond dipoles cancel as vectors. Equal dipoles cancel in arrangements such as linear CO2, trigonal planar BF3 and tetrahedral CCl4. In bent H2O and pyramidal NH3 they do not cancel. It is the dipoles that cancel, not the bonds.
| Molecule | Shape | Polar? | Reason |
|---|---|---|---|
| CO2 | Linear | No | Two equal C=O dipoles point in opposite directions and cancel |
| BF3 | Trigonal planar | No | Three equal dipoles at 120° cancel |
| CCl4 | Tetrahedral | No | Four equal dipoles cancel |
| XeF4 | Square planar | No | Dipoles cancel even though Xe has two lone pairs |
| H2O | Bent | Yes | Dipoles do not cancel |
| NH3 | Pyramidal | Yes | Dipoles do not cancel |
| CH3Cl | Tetrahedral | Yes | C–Cl dipole is not matched by the C–H bonds |
Do not say "molecules with lone pairs are polar": XeF4 shows this is false.
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Dipole cancellation: CO₂ and CCl₄ vs H₂O and CH₃Cl
Labels to include:
- Bond dipole arrows from δ+ to δ−
- Symmetry in CO₂ and CCl₄: arrows cancel
- Resultant dipole in H₂O and CH₃Cl
- δ+ and δ− labels on atoms
4. London forces
Electrons are always moving. At any instant, the electron cloud in a molecule may be uneven, creating an instantaneous dipole. This induces a dipole in a neighbouring molecule, and the opposite partial charges attract. These are London (dispersion) forces. They act between all molecules, including non-polar ones and noble-gas atoms.
London forces are stronger when:
- the molecule has more electrons, making its electron cloud more easily distorted;
- the molecule has a larger contact surface area. Unbranched molecules can make more extensive contact than compact branched isomers of the same formula, so they have stronger London forces and higher boiling points.
Down Group 17, from F2 to I2, the molecules have more electrons, so London forces and boiling points increase. Boiling points also rise along a homologous series as the chain gets longer.
5. Permanent dipole–dipole forces
Polar molecules have permanent dipoles. The δ+ end of one molecule attracts the δ− end of a neighbour. These forces act in addition to London forces, never instead of them.
6. Hydrogen bonding
A hydrogen bond forms when hydrogen is covalently bonded to N, O or F, and is attracted to a lone pair on an N, O or F atom in another molecule.
- The N–H, O–H or F–H bond is very polar, so the H is strongly δ+.
- Draw the hydrogen bond as a dotted line from the δ+ H to the lone pair on the N, O or F of the other molecule.
- Show the δ+ and δ− charges and the lone pair. The X–H···Y arrangement is close to linear (about 180°).
Donors and acceptors
Ethanol (CH3CH2OH) has an O–H group and lone pairs on O, so it can hydrogen bond with itself. Ethanal (CH3CHO) has lone pairs on O but no H bonded to O, so it cannot hydrogen bond with itself; it can still accept hydrogen bonds from water.
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Hydrogen bond between two water molecules
Labels to include:
- δ+ on H, δ− on O
- Lone pair on the O of the second molecule
- Dotted line from H to that lone pair
- O–H···O close to 180°
The dotted line ends at the lone pair of the oxygen in the other molecule, not at its hydrogen.
7. Comparing boiling points
Don't apply a fixed ranking such as "hydrogen bonds > dipoles > London" when the molecules differ in size. Compare the total intermolecular forces.
8. Ice and anomalous hydrides
H2O, NH3 and HF have much higher boiling points than you would expect from the trend in the heavier hydrides of their groups (H2S, PH3, HCl). This is because they form hydrogen bonds, which need extra energy to overcome.
In ice, each water molecule forms up to four hydrogen bonds: two through its own H atoms and two to its lone pairs. This makes an open tetrahedral network, with molecules held further apart on average than in liquid water. So ice is less dense than water. On melting, some hydrogen bonds break and the network partly collapses, so the molecules pack more closely. (This tetrahedral arrangement between molecules is separate from the 104.5° angle inside each water molecule.)
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Ice: open hydrogen-bonded network
Labels to include:
- Each water molecule: two covalent O–H bonds (solid lines)
- Each water molecule hydrogen bonded to four neighbours: two H bonds donated through its own H atoms, two accepted at the lone pairs on its O
- Tetrahedral arrangement of the four neighbours around each O
- Open spaces in the lattice
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Boiling points of Group 14–17 hydrides
Labels to include:
- x-axis: period 2 to 5
- y-axis: boiling point
- Group 14 rises smoothly
- H₂O, HF and NH₃ well above their group trend
Shape only: no data values are given here. The key feature is that the period 2 hydrides of Groups 15–17 sit above the trend.
9. The charged-rod test
A thin stream of a polar liquid (such as water) bends towards a charged rod: the permanent dipoles turn so that their oppositely charged end faces the rod, and are attracted. A non-polar liquid such as cyclohexane is barely affected. This is a simple observation, not a precise measure of how polar a substance is.
10. Quick checks
Finesse practice: indicative answers to check your reasoning, not official mark allocations.
Q1. Define electronegativity.Show answer
The power of an atom to attract the pair of electrons in a covalent bond.
Q2. Why is BF₃ non-polar even though B–F bonds are polar?Show answer
BF3 is trigonal planar and symmetrical, with three identical B–F bonds. Their dipoles cancel, so there is no overall dipole.
Q3. Why does pentane boil at a higher temperature than 2,2-dimethylpropane (same formula)?Show answer
Pentane is unbranched, so its molecules can make more extensive contact than the compact branched isomer. The London forces are stronger and need more energy to overcome.
Q4. Can propanone (CH₃COCH₃) form hydrogen bonds with itself? With water?Show answer
Not with itself: it has no H bonded to O. With water, yes: the O lone pairs can accept hydrogen bonds from water's O–H.
Q5. Why is ice less dense than liquid water?Show answer
In ice, hydrogen bonds hold the molecules in an open tetrahedral network, further apart on average. When ice melts, some hydrogen bonds break and the molecules move closer together.
11. Sources
Sources and examiner guidance (reviewed 1 October 2026)
- Chemrevise — AQA 1.3 Bonding revision guide (N. Goalby) — primary content reference (electronegativity, polarity, intermolecular forces)
- AQA 7405 specification — 3.1.3 Bonding — 3.1.3.6 Bond polarity, 3.1.3.7 Forces between molecules
- AQA 7404/1 mark scheme, June 2022 — Q04.1–04.5: hydrogen bonds, electronegativity, polarity, CBr₄ vs CHBr₃
- AQA 7404/1 examiner report, June 2022 — Q4: omitted partial charges and lone pairs, wrong H-bond endpoint, covalent bonds broken on boiling
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