AQA A-Level Chemistry 7405 · 3.1.1 Atomic structure

Part 3: Electron configurations

All four parts available · diagram placeholders included. Reviewed 1 October 2026.

1. Shells, sub-shells and orbitals

Electrons are arranged in shells (principal energy levels, n = 1, 2, 3…). Each shell is split into sub-shells (s, p, d), and each sub-shell contains orbitals.

An orbital is a region of space where there is a high probability of finding an electron. Each orbital can hold a maximum of 2 electrons, with opposite spins.

Sub-shells
Sub-shellOrbitalsMax electronsShape
s12Spherical
p36Dumbbell, three at right angles (x, y, z)
d510More complex (shapes not needed)
f (beyond Kr)714Not needed for Z ≤ 36

Shell 1 has only 1s. Shell 2 has 2s and 2p. Shell 3 has 3s, 3p and 3d. Shell 4 starts with 4s and 4p (and 4d and 4f beyond Kr).

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Shapes of s and p orbitals

Labels to include:

  • s orbital: sphere centred on nucleus
  • pₓ, p_y, p_z: dumbbells along x, y and z axes
  • Nucleus at the origin

An s orbital is a sphere around the nucleus. Each p orbital has two lobes on opposite sides of the nucleus, and the three p orbitals point along axes at right angles to each other.

2. Filling order and rules

For atoms up to krypton, sub-shells fill in this order:

1s 2s 2p 3s 3p 4s 3d 4p

  • Lowest energy first: electrons go into the lowest-energy available sub-shell.
  • Single first, then pair: within orbitals of equal energy (e.g. the three 2p orbitals), electrons go in one per orbital with parallel spins before any pairing. This is because paired electrons in the same orbital repel each other.
  • Two per orbital, opposite spins: no orbital holds more than two electrons.

The rule "4s before 3d" describes the filling order of atoms. It does not mean 4s is always lower in energy: once the 3d orbitals are occupied, 4s electrons are the first to be removed when transition metal ions form.

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Energy-level diagram of sub-shells to 4p

Labels to include:

  • Energy axis (increasing upward)
  • 1s, 2s, 2p (3 boxes), 3s, 3p (3 boxes), 4s, 3d (5 boxes), 4p (3 boxes)
  • 4s drawn just below 3d for filling

3. Electrons-in-boxes

Nitrogen: 1s2 2s2 2p3

2p
2s
1s

The three 2p electrons are each on their own, with parallel spins.

Oxygen: 1s2 2s2 2p4

2p
2s
1s

The fourth 2p electron has to pair up, giving one pair and two single electrons.

4. Writing configurations

In 3p4, the 3 is the shell, p is the sub-shell, and the superscript 4 is the number of electrons in that sub-shell. Check: the superscripts add up to the total number of electrons.

Example: sulfur (Z = 16) is 1s2 2s2 2p6 3s2 3p4, and 2 + 2 + 6 + 2 + 4 = 16 ✓.

A shortened form uses the previous noble gas: [He] = 1s2, [Ne] = 1s2 2s2 2p6, [Ar] = 1s2 2s2 2p6 3s2 3p6. So sulfur is [Ne] 3s2 3p4. If a question asks for the full configuration, write out every sub-shell.

5. Configurations from H to Kr

Ground-state electron configurations of neutral atoms, Z = 1 to 36
ElementZConfiguration
H hydrogen11s1
He helium21s2
Li lithium3[He] 2s1
Be beryllium4[He] 2s2
B boron5[He] 2s2 2p1
C carbon6[He] 2s2 2p2
N nitrogen7[He] 2s2 2p3
O oxygen8[He] 2s2 2p4
F fluorine9[He] 2s2 2p5
Ne neon10[He] 2s2 2p6
Na sodium11[Ne] 3s1
Mg magnesium12[Ne] 3s2
Al aluminium13[Ne] 3s2 3p1
Si silicon14[Ne] 3s2 3p2
P phosphorus15[Ne] 3s2 3p3
S sulfur16[Ne] 3s2 3p4
Cl chlorine17[Ne] 3s2 3p5
Ar argon18[Ne] 3s2 3p6
K potassium19[Ar] 4s1
Ca calcium20[Ar] 4s2
Sc scandium21[Ar] 3d1 4s2
Ti titanium22[Ar] 3d2 4s2
V vanadium23[Ar] 3d3 4s2
Cr chromium24[Ar] 3d5 4s1
Mn manganese25[Ar] 3d5 4s2
Fe iron26[Ar] 3d6 4s2
Co cobalt27[Ar] 3d7 4s2
Ni nickel28[Ar] 3d8 4s2
Cu copper29[Ar] 3d10 4s1
Zn zinc30[Ar] 3d10 4s2
Ga gallium31[Ar] 3d10 4s2 4p1
Ge germanium32[Ar] 3d10 4s2 4p2
As arsenic33[Ar] 3d10 4s2 4p3
Se selenium34[Ar] 3d10 4s2 4p4
Br bromine35[Ar] 3d10 4s2 4p5
Kr krypton36[Ar] 3d10 4s2 4p6

6. Period 4 and the exceptions Cr and Cu

After argon, 4s fills first: K is [Ar] 4s1 and Ca is [Ar] 4s2. Next, 3d fills from Sc ([Ar] 3d1 4s2) to Zn ([Ar] 3d10 4s2). Then 4p fills, ending at Kr ([Ar] 3d10 4s2 4p6).

7. Configurations of ions

Start from the neutral atom, then add or remove electrons. The number of protons (Z) never changes.

  • Main group: remove electrons from (or add them to) the outer sub-shell.
  • Transition metals: remove the 4s electrons first, then 3d.
Ion configurations
IonElectronsConfiguration
Ca²⁺20 − 2 = 18[Ar]
N³⁻7 + 3 = 10[Ne]
Fe²⁺26 − 2 = 24[Ar] 3d6
Fe³⁺26 − 3 = 23[Ar] 3d5
Cr³⁺24 − 3 = 21[Ar] 3d3
Cu⁺29 − 1 = 28[Ar] 3d10
Cu²⁺29 − 2 = 27[Ar] 3d9

Worked: Fe³⁺. Fe is [Ar] 3d6 4s2 (26 electrons). Removing both 4s electrons and then one 3d electron leaves 23 electrons: [Ar] 3d5. Written in full, that is 1s2 2s2 2p6 3s2 3p6 3d5.

8. Blocks of the periodic table

An element's block depends on the sub-shell that its highest-energy electrons are filling:

  • s block: Groups 1 and 2, plus helium (1s2)
  • p block: Groups 13–18, except helium
  • d block: the central transition-metal region (Sc to Zn in Period 4)

Don't decide the block from whatever sub-shell happens to be written last. For a neutral atom, the period is its outermost occupied shell. For a main-group element, its outer-shell electrons are the s and p electrons in that shell.

9. Finesse practice

Original Finesse practice questions, not AQA past-paper questions.

Q1. Give the electron configuration of a chromium atom.Show answer

[Ar] 3d5 4s1, which is 1s2 2s2 2p6 3s2 3p6 3d5 4s1 (24 electrons).

Q2. Give the configuration of Cu²⁺.Show answer

Cu is [Ar] 3d10 4s1. Remove the 4s electron, then one 3d electron: [Ar] 3d9 (27 electrons).

Q3. Write the full electron configuration of bromine (Z = 35).Show answer

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5. Check: 2+2+6+2+6+10+2+5 = 35 ✓.

Q4. Why do the three 2p electrons in nitrogen occupy separate orbitals rather than pairing?Show answer

The 2p orbitals have the same energy. Electrons in the same orbital repel each other, so they occupy separate orbitals with parallel spins before pairing, which gives lower overall energy.

10. Sources

Sources and examiner guidance (reviewed 1 October 2026)

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