Convert between a monomer and a polymer repeat unit, then use chain interactions to explain properties and plasticisation.
From one double bond to a long chain
Addition polymerisation joins many alkene monomers into a long molecule. For a simple monoalkene, the C=C becomes a C–C single bond within the backbone and new bonds join neighbouring units. All the atoms of the monomer are retained in the ideal repeat unit; no small molecule such as water is eliminated.
Do not say the entire double bond disappears and the carbons separate. The two original alkene carbons remain adjacent in the chain. Polymerisation conditions depend on the monomer and process; no single catalyst or pressure suits every addition polymer.
Draw the two backbone carbons first
For propene, begin with CH₂=CHCH₃. Change the double bond to a single bond and extend one bond outwards from each of these two carbons. Keep CH₃ attached to the second carbon. The repeat unit is –CH₂–CH(CH₃)–.
For a polymer equation, put brackets around the unit with bonds passing through the brackets and n outside; write n before the monomer on the reactant side. If asked for exactly one repeat unit, show one unit and its continuation bonds. If asked for several units, repeat the pattern without inventing terminal groups.
| Monomer | Repeat-unit connectivity | Polymer name |
|---|---|---|
| CH₂=CH₂ | –CH₂–CH₂– | poly(ethene) |
| CH₂=CHCH₃ | –CH₂–CH(CH₃)– | poly(propene) |
| CH₂=CHCl | –CH₂–CH(Cl)– | poly(chloroethene), PVC |
| CF₂=CF₂ | –CF₂–CF₂– | poly(tetrafluoroethene), PTFE |
| CH₂=CHC₆H₅ | –CH₂–CH(C₆H₅)– | poly(phenylethene) |
Diagram placeholder
Propene polymerisation and the bracket convention
Labels to include:
- n propene molecules
- two-carbon backbone
- CH₃ branch retained
- single backbone bonds
- continuation bonds through brackets
- n outside polymer brackets
Arrange H,H around one alkene carbon and H,CH₃ around the other before converting C=C to C–C. Draw one extra bond from each end, bracket the unit and place n outside for the equation. The methyl side group must not be inserted as a third backbone carbon.
Recover the monomer from a chain segment
Find the smallest repeating pattern with the original two alkene-derived backbone carbons. Cut its two continuation bonds and restore C=C between those carbons. Keep the substituents on the same carbons.
For –CH(CH₃)–CH(CH₃)–, the monomer is CH₃CH=CHCH₃, but-2-ene. A repeat unit need not contain a CH₂ group. Redrawing the unit from the other end does not create a different polymer.
Separate bonds within chains from forces between chains
In a simple polyalkene backbone, strong C–C and C–H bonds and the lack of reactive functional groups help explain low chemical reactivity. Breaking down the chain is different from melting the material. On softening or melting, chains gain mobility as intermolecular constraints are overcome; the backbone does not normally break.
Long chains have many points of contact and substantial London attractions. Molecular mass, branching, packing and crystallinity influence properties, so “all polymers have the same melting point” is not meaningful. Their resistance to chemical and biological attack makes many addition polymers durable but also persistent as waste.
Why a plasticiser makes PVC flexible
PVC has polar C–Cl bonds and attractions between chains that restrict movement, giving unplasticised PVC useful rigidity for applications such as window frames and pipes. Plasticiser molecules fit between chains, reducing effective interchain attractions and making sliding easier.
Plasticised PVC is more flexible and can be used in cable insulation and flexible sheeting. The plasticiser does not normally soften PVC by cutting its covalent backbone. Choose a material by linking its structure and interactions to the required property.
Recycling can conserve material, but sorting, contamination and changes in properties can limit reuse. Burning can recover energy but carbon-containing polymers release CO₂; chlorine-containing PVC also needs control of acidic combustion products. These trade-offs do not mean all polymers are biodegradable or all can be recycled together.
Quick checks
Original Finesse questions. Reveal the indicative worked solutions after attempting each question; these are not official AQA mark allocations.
Q1. Give the repeat-unit connectivity of poly(but-1-ene).Show answer
–CH₂–CH(CH₂CH₃)–. Only the original double-bond carbons enter the backbone; the ethyl group remains a side group.
Q2. Deduce the monomer for –CH₂–C(CH₃)₂–.Show answer
CH₂=C(CH₃)₂, 2-methylpropene. Restore a double bond between the two backbone carbons and retain both methyl substituents on the second.
Q3. Why is the ideal atom economy of addition polymerisation 100%?Show answer
All monomer atoms are incorporated into the polymer; no small coproduct is eliminated. This does not guarantee 100% conversion or zero process waste.
Q4. Estimate the number of units in a poly(ethene) chain with relative molecular mass 56 000, ignoring end groups.Show answer
Repeat-unit mass C₂H₄ = 28.0. Number = 56 000/28.0 = 2000.
Q5. Explain why plasticised PVC is more flexible than unplasticised PVC.Show answer
Plasticiser molecules separate chains and reduce effective attractions between them, so the chains can move past each other more easily. The explanation concerns interchain interactions rather than breaking C–C backbone bonds.
Sources
Sources and examiner guidance (reviewed 2 October 2026)
- Chemrevise: Alkenes — Coverage checklist, pp1–4; original teaching examples and practice.
- AQA 7405 specification — 3.3.4.1–3.3.4.3.
Finesse Tuition is not endorsed by AQA or Chemrevise. All explanations and examples here are our own.
